9x - 7i > 3 (3x - 7u), for i - Tree of Souls - An Avatar Community Forum
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  #1  
Old 11-04-2010, 11:55 AM
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Default 9x - 7i > 3 (3x - 7u), for i

Cute.
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  #2  
Old 11-04-2010, 12:00 PM
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please, I have fall break...

NO DAMN MATH!!!




...





...





...






interesting nonetheless
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Old 11-04-2010, 04:50 PM
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Is 7i not an imaginary number?
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Old 11-04-2010, 04:56 PM
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Quote:
Originally Posted by Aihwa View Post
Is 7i not an imaginary number?
It can be a vector.

Do these represent vectors?
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Old 11-04-2010, 05:00 PM
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Quote:
Originally Posted by Banefull View Post
It can be a vector.

Do these represent vectors?


I get it... Just treat it like a normal variable. You'll see it.



Eltu.


Five foot rule.
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  #6  
Old 11-04-2010, 05:01 PM
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Aww.
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Old 11-04-2010, 05:10 PM
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That is not what I meant by vectors, yes they could be variables but they could also represent different dimensions in a geometrical plane. It is very common to assign the letter i for y-axis. You could assign any symbol you wanted to I guess to represent any dimension.

Both sides have 9 units in one direction (I will call it width), one has -7 units in another (I could call height), and the the other size has -21 units in the third dimension (depth).

To solve this we would have to use the cross product (sometimes called the vector product) since we are using vectors in three dimensions (which I am too lazy to do as I am also too tired of math problems). We could actually verify that one vector is larger than the other.

EDIT: or if they're just variables then I'm over thinking it but it would sitll have a specific answer

Last edited by Banefull; 11-04-2010 at 05:43 PM.
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Old 11-04-2010, 05:19 PM
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Quote:
Originally Posted by Banefull View Post
That is not what I meant by vectors, yes they could be variables but they could also represent different dimensions in a geometrical plane. It is very common to assign the letter i for y-axis. You could assign any symbol you wanted to I guess to represent any dimension.

Both sides have 9 units in one direction (I will call it width), one has -7 units in another (I could call height), and the the other size has -21 units in the third dimension (depth).

To solve this we would have to use the cross product (sometimes called the vector product) since we are using vectors in three dimensions (which I am too lazy to do as I am also too tired of math problems). We could actually verify that one vector is larger than the other.

EDIT: or if they're just variables then I'm over thinking it
Their just variables. Solve it like a simple equation.
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Old 11-04-2010, 05:21 PM
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How do you know that? This could also be a boolean algebraic expression rather than an equation in the real number system. Such a statement could have an output of 0 or 1.
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Old 11-04-2010, 05:22 PM
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Quote:
Originally Posted by Banefull View Post
How do you know that? This could also be a boolean algebraic expression rather than an equation in the real number system. Such a statement could have an output of 0 or 1.


The reason they were selected was for the end to make sense. It works. Trust me. Just solve it.
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Old 11-04-2010, 05:23 PM
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But the other 2 cases could work also and make sense?
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  #12  
Old 11-04-2010, 05:26 PM
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Quote:
Originally Posted by Banefull View Post
But the other 2 cases could work also and make sense?

They might make sense but they wont be the answer Eltu is looking for.
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Old 11-04-2010, 05:27 PM
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Do we know if Eltu made up this problem? He could have copied it from somewhere else. And if it was by Eltu, how do you know what his original intent was? You =/= Eltu.

This belongs in the debate forum imho.
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  #14  
Old 11-04-2010, 05:43 PM
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It's meant as en expression - simplify it, solve out i.

(not sure if I got the terms right, no good with english math )
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Old 11-04-2010, 05:55 PM
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Not imaginary numbers, here i is just equivalent to x
This goes well with the equation
Quote:
(x^2 + 9/4y^2 + z^2 - 1)^3 - x^2 * z^3 - 9/80y^2 * z^3 = 0 for -3 < x,y,z < 3
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